Which is the correct order of ease of carbon dioxide production by heating the group II metal carbonates?
A) [tex]BaCO_{3} > SrCO_{3} > CaCO_{3} > MgCO_{3}[/tex]
B) [tex]MgCO_{3} > CaCO_{3} > SrCO_{3} > BaCO_{3}[/tex]
C) [tex]CaCO_{3} > MgCO_{3} > BaCO_{3} > SrCO_{3}[/tex]
D) [tex]SrCO_{3} > BaCO_{3} > CaCO_{3} > MgCO_{3}[/tex]
Answer:
Explanation:
The correct option is A:
[tex]BaCO_{3} > SrCO_{3} > CaCO_{3} > MgCO_{3}[/tex]
On the periodic table, carbonates required stronger heating as one does down the groupings in order for them to decompose. The implication is that the stability of compounds will increase from [tex]MgCO_{3}[/tex] to [tex]BaCO_{3}[/tex] .
So the carbonates will be stable according to the following order:
[tex]BaCO_{3} > SrCO_{3} > CaCO_{3} > MgCO_{3}[/tex], thus making B the correct answer.
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