Answer: Greater than or equal to 2.
Step-by-step explanation:
Given
Function is [tex]f(x)=2x^2+5\sqrt{x-2}[/tex]
The entity inside a square root is always positive i.e. greater than equal to zero
[tex]\therefore \ x-2\geq 0\\\Rightarrow x\geq2[/tex]
So, the domain of the function is all real numbers greater than or equal to 2.
