Answer:
Step-by-step explanation:
The average is 81 a low B, but if you throw out the low score it rises to 88.8, a high B.
I would use the median 88, 89 since it is higher and is a more accurate representation of the majority of the class
A) Yes, we can say that the class did well.
B)I would choose median to describe the data.
How to find mean, median and mode?
Mean simply means average of the data given, Here,
[tex]Mean=\dfrac{89+87+93+90+12+91+88+87+83+91}{10} =80.9[/tex]
Median is the value of data set (when arranged in ascending order) that divides it into two sets and is often called the middle number. When no. pf values in data set is even, the median is N/2.
Here,
[tex]Median=\dfrac{10}{2} ^{th}=5^{th} term=88[/tex] (data taken in ascending order)
Mode is the value which has largest frequency among the all the other values.
Here, Mode is 87 and 91.
A) The class did well if we consider the data from point of view of its median and mode, but the average value is a bit low as we have a drastically low value that is 12.
B) I would describe the data by median because the class mean is very low and as there are 2 mode values, it is not the best representation of the score. The median of the set is a high and singleton value, therefore the most accurate measure of central tendency would be median.
To know more about mean, median, mode refer:https://brainly.com/question/25750771
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