Answer:
Step-by-step explanation:
Quadratic equation has been given as,
[tex]y=-x^{2} +6x+4[/tex]
Converting this equation into vertex form,
[tex]y=-(x^{2}-6x)+4[/tex]
[tex]y=-[x^{2}-2(3x)+9-9]+4[/tex]
[tex]y=-[x^{2}-2(3x)+3^2]+4+3^2[/tex]
[tex]y=-(x-3)^2+4+9[/tex]
[tex]y=-(x-3)^2+13[/tex]
By comparing this equation with the vertex form of a quadratic equation,
y = (x - h)² + k
Here, (h, k) is the vertex of the parabola.
Vertex of the parabola → x = 3, y = 13
Axis of symmetry → x = 3
