Answer:
The locations of each irrational number are the following:
[tex]\sqrt{16}[/tex] - Point [tex]a[/tex]
[tex]\sqrt{27}[/tex] - Point [tex]b[/tex]
[tex]\sqrt{32}[/tex] - Point [tex]c[/tex]
Step-by-step explanation:
[tex]\sqrt{16}[/tex] is an irrational number that is also rational, since [tex]4^{2} = 16[/tex]. Then, [tex]\sqrt{16}[/tex] must be point [tex]a[/tex].
Both [tex]\sqrt{27}[/tex] and [tex]\sqrt{32}[/tex] are greater than [tex]\sqrt{25} = 5[/tex] and less than [tex]\sqrt{36} = 6[/tex]. Then, both are between 5 and 6. Since [tex]\sqrt{27} < \sqrt{32}[/tex], [tex]\sqrt{27}[/tex] must be point [tex]b[/tex] and [tex]\sqrt{32}[/tex] must be point [tex]c[/tex].
