Answer:
a) Y = 15,587(1.02)^t
where Y is the population at a certain year t after 2010
b) 22,262 persons
Step-by-step explanation:
a) we want to write an exponential equation;
Generally, we have this as;
Y = P(1 + r)^t
where Y is the value at a time t
P is the initial value
r is the rate of change
t is the time
From the question;
P is 15,587
r is 2% = 2/100 = 0.02
So, we have the equation as;
Y = 15,587(1 + 0.02)^t
Y = 15,587(1.02)^t
b) The population in 2028
To get this, we need the value of t
What we have to do here is to subtract 2010 from 2028
We have this as; 2028 - 2010 = 18
So substituting this value into the exponential equation above, we have
Y = 15,587(1 + 0.02)^18
Y = 15,587(1.02)^18
= 22,262
