Answer:
[tex]6molCO_2[/tex]
Explanation:
Hello there!
In this case, according to the described reaction, we can set up the chemical equation as shown below:
[tex]NaHCO_3+CH_3COOH\rightarrow CO_2+H_2O+CH_3COONa[/tex]
We can evidence the 1:1 mole ratio of baking soda (NaHCO3) to CO2 and therefore the produced moles of latter are calculated as shown below:
[tex]6molNaHCO_3*\frac{1molCO_2}{1molNaHCO_3} \\\\6molCO_2[/tex]
Best regards!