Answer:
[tex]x = -2[/tex]
Step-by-step explanation:
Given
[tex]y=\frac{-3}{(x+2)^2}+3[/tex]
[tex]y = - 3[/tex]
[tex]y = 0[/tex]
The question has confusing details because the height of a shape do not relate to the given parameters.
A more complete question found on the brainly shows that the complete question asks for the asymptote of the function.
To do this, we have:
[tex]y=\frac{-3}{(x+2)^2}+3[/tex]
Take LCM
[tex]y = \frac{-3 + 3(x+2)^2}{(x+2)^2}[/tex]
Equate the denominator to 0
[tex](x + 2)^2 = 0[/tex]
Take square roots of both sides
[tex]x + 2 = 0[/tex]
Solve for x
[tex]x = -2[/tex]
Hence, the asymptote is at [tex]x = -2[/tex]
