Answer:
The lengths of the legs of the triangle are 10 inches.
Step-by-step explanation:
The lengths of the legs (l) can be found from the area:
[tex] A = \frac{bh}{2} [/tex]
Where:
A: is the area = 50 in²
b: is the base
h: is the height
Since the right triangle is isosceles, the base and the height are the same. The height and the base are the legs (l).
[tex] b = h = l [/tex]
Then the lengths of the legs are:
[tex] A = \frac{l^{2}}{2} [/tex]
[tex] l = \sqrt{2A} = \sqrt{2*50} = 10 in [/tex]
Hence, the lengths of the legs of the triangle are 10 inches.
I hope it helps you!
