Answer:
speed of the rocket is 6feet
Step-by-step explanation:
Complete question
The height in feet, h, of a model rocket t seconds after launch is given by the equation h(t) = 3+70t - 16t^2. The average rate of change in h(t) between t = 1 second and t = 3 second is 6. What does the average rate of change tell you about the rocket?
Note that the average rate is also known as the speed
Average rate = h(3)-h(1)/3 - 1
h(3) = 3+70(3) - 16(3)^2
h(3) = 3 + 210 - 144
h(3) = 69
h(1) = 3+70(1) - 16(11)^2
h(1) = 3 + 70 - 16
h(1) = 73 -16
h(1) = 57
Average rate = 69-57/3-1
Average rate = 12/2
Average rate = 6ft/s
This shows that the speed of the rocket is 6feet
