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The diagram below shows a 1.0 x 105newton truck at rest on a hill that makes an angle of 8.0Β° with the
horizontal. What is the component of the truck's weight parallel to the hill? (hint: the weight was already
calculated, also you can use the work area to help you solve this.]

The diagram below shows a 10 x 105newton truck at rest on a hill that makes an angle of 80 with the horizontal What is the component of the trucks weight parall class=

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Answer:

[tex]it \: is \: mg \sin(8.0 \degree) \\ = 1.0 \times 10 {}^{5} \times \sin(8.0 \degree) \\ = 9.9 \times 10 {}^{4} newtons[/tex]

onyebuchinnaji

The component of the truck's weight parallel to the hill is 13,917.31 N.

The given parameters:

  • Weight of the truck, W = 1.0 x 10⁡ N
  • Inclination of the hill, ΞΈ = 8⁰

The component of the truck's weight parallel to the hill is calculated as follows;

[tex]W_x = mg \times sin(\theta)\\\\W_x = W \times sin(\theta)\\\\W_x = 1\times 10^5 \times sin(8)\\\\W_x = 13,917.31 \ N[/tex]

Thus, the component of the truck's weight parallel to the hill is 13,917.31 N.

Learn more about parallel forces here: https://brainly.com/question/9719731

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