Answer:
1) [tex]-2/3(x+5)+4(x+5)-10/3(x+5)[/tex]
[tex]=4(x+5)-10/3(x+5)-2/3(x+5)[/tex]
[tex]=4(x+5)-(x+5)[10/3+2/3][/tex]
[tex]=4(x+5)-(x+5)(10+2/3)[/tex]
[tex]=4(x+5)(12/3)(x+5)[/tex]
[tex]=4(x+5)-4(x+5)[/tex]
[tex]=0[/tex]
[tex]So, Jada~ is ~correct, because ~ by ~adding~negative ~term~we ~get~the~same~value\\of~negative~term~ so, both ~are ~ equaled~ out ~ and ~ get~ 0[/tex]
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hope it helps...
have a great day!!
