Answer:
4.5x10⁻¹¹M is the hydronium ion concentration
Explanation:
To solve this concentration we must find, as first, the molar concentration of OH-, [OH-]. With [OH-] we can find pOH, pH, and [H+], hydronium ion concentration, as follows:
[OH-]:
1mol of Ca(OH)2 contains 2 moles of OH-:
0.00011M Ca(OH)2 * (2moles OH- / 1mol Ca(OH)2) = 0.00022M OH-
pOH:
pOH = -log[OH-]
pOH = 3.658
pH:
pH = 14-pOH
pH = 10.34
[H+]:
10^-pH
4.5x10⁻¹¹M is the hydronium ion concentration
