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Answer please: A box weighing 890 N is pulled along a horizontal surface by means of a string which is at 30° above the horizontal. If the coefficient of kinetic friction is 0.2 and the box is accelerated at 0.8 m/s2, what is the tension in the string?

Answer please A box weighing 890 N is pulled along a horizontal surface by means of a string which is at 30 above the horizontal If the coefficient of kinetic f class=

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Jerushaanjelin

Answer:

vertical problem:

normal force = weight - string up force

= 890 - T sin 30 = 890-.5 T

horizontal problem:

T cos 30 - .2(890-.5T) = (890/9.81) (0.8)

solve for T

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