Answer: 0.4 V
Explanation:
Given
The area of the loop is [tex]A=0.8\ m^2[/tex]
The magnetic field is changing at the rate of [tex]\dot{B}=-0.5\ T/s[/tex]
Induced EMF is given by
[tex]E=-\dfrac{d\phi }{dt}\\\\E=-\dfrac{d(B\cdot A)}{dt}\\\\E=-A\dfrac{dB}{dt}\\E=-0.8\times (-0.5)\\E=0.4\ V[/tex]
The magnitude of induced emf is 0.4 V