Answer:
c. 0.0398.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
To solve this question, we find each separate probability, and then multiply them.
First winner is a chemistry major
23 chemistry majors out of 61 students. So
[tex]P(A) = \frac{23}{61}[/tex]
Second winner is a chemistry major:
Considering the first event, 22 chemistry majors out of 60 students. So
[tex]P(B) = \frac{22}{60}[/tex]
Third winner is an undecided major;
Considering the first two events, 17 undecided out of 59 students. So
[tex]P(C) = \frac{17}{59}[/tex]
Desired probability:
[tex]P(A \cap B \cap B) = P(A)P(B)P(C) = \frac{23}{61} \times \frac{22}{60} \times \frac{17}{59} = \frac{23*22*17}{61*60*59} = 0.0398[/tex]
So option c.