Respuesta :
Answer:
Probability that the spinner stop on an even number or a multiple of 3 = [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
Given - A spinner has regions numbered 1 through 18.
To find - What is the probability that the spinner, spun once, will stop on an even number or a multiple of 3?
Solution -
Given that,
A spinner has regions numbered 1 through 18.
So,
The sample space, S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18}
i.e.
n(S) = 18
Now,
Let A be the outcomes that gives even number or a multiple of 3,
Then
A = {2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18}
i.e.
n(A) = 12
∴ we get
Probability that the spinner stop on an even number or a multiple of 3 = [tex]\frac{n(A)}{n(S)}[/tex]
= [tex]\frac{12}{18}[/tex]
= [tex]\frac{2}{3}[/tex]
i.e.
Probability that the spinner stop on an even number or a multiple of 3 = [tex]\frac{2}{3}[/tex]
