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Answer:

0.900 Jg^-1℃^-1

Explanation:

Given that;

H = mcθ

H = heat added

m = mass of aluminium

c = specific heat of aluminum

θ = increase in temperature

Making c the subject of the formula;

c = H/mθ

c = 207 J/28.4 g * 8.1oC

c = 0.900 Jg^-1℃^-1

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