A gas has an initial volume of 50.0 L at 205 K. If the temperature increases from to 590. K, what is
the resulting volume?

Respuesta :

Answer:

Heyy Mason, I donʻt know if you got the answer already but I was also trying to find the answer haha and came across this. Might as well help you since I eventually stopped being lazy and did the calculations...The answer is 144 L.

Explanation:

Use Charles Law to solve this

V1 = 50.0L

T1 = 205K

V2 = ?

T2 = 590K

using V1/T1 = V2/T2 plug in the numbers

50.0L/205K = V2/590K

Switch it around so V2 is isolated

V2 = 590K(50.0L/205K)

cancel out the K

solve

you get 143.90243

round to 144