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Does the quadratic function
y = 3x2 + 7x - 8
have one, two or no real zeros?
Utilize the quadratic formula to
determine the answer.
[?] real zeros

Respuesta :

Answer:

Two real roots

Step-by-step explanation:

The portion of the quadratic formula that determines the number of roots is

b² - 4ac

If it's positve there are two real roots

If it's zero there is one real root

If it's negative there are no real roots

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b² - 4ac = 7² - 4(3)(-8)

b² - 4ac =  49 + 96

b² - 4ac =  145

Two real roots since 145 is positive

The quadratic equation has two real zeroes

What is quadratic equations?

The polynomial equations of degree two in one variable of type f(x) = ax2 + bx + c = 0 and with a, b, c, and R R and a 0 are known as quadratic equations. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f. (x). The roots of the quadratic equation are the values of x that fulfill the equation (, ).

It is a given that the quadratic equation has two roots. Roots might have either a real or imaginary nature.

What is quadratic formlua?

D=b²-4ac

x=(-b±√(b²-4ac))/2a

y = 3x² + 7x - 8

On comparing with ax²+bx+c, we get

a=3, b=7 and c=-8

Using Quadratic formula

D=b²-4ac

   =7²+4x3x8

   =49+96

     =145>0

Hence it has real zeroes

Learn more about Quadratic equation,

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