Answer:
The maximum height of the ball will be "16.53 m".
Explanation:
Given that,
[tex]V_{final} = 18 \ m/s[/tex]
As we know,
The initial as well the final height on the ball will be same after it reaches it's maximum height.
then,
⇒ [tex]V_{final}=V_{initial}[/tex]
where, [tex]V_{initial} = \sqrt{2gh}[/tex]
[tex]=\sqrt{2\times 9.8\times h}[/tex]
[tex]=\sqrt{19.6h}[/tex]
hence,
The max height of the ball will be:
⇒ [tex]18=\sqrt{19.6h}[/tex]
[tex]19.6h=324[/tex]
[tex]h=\frac{324}{19.6}[/tex]
[tex]=16.53 \ m[/tex]
