Answer:
The correct answer is "[tex]12\times 10^{-6} \ C[/tex]".
Explanation:
Given that,
[tex]Q1=+4.0\times 10^{-6} \ C[/tex]
and,
[tex]Q2=+2.0\times 10^{-5} \ C[/tex]
or,
[tex]=20\times 10^{-6} \ C[/tex]
then,
The total charge will be:
⇒ [tex]Q =Q1+Q2[/tex]
[tex]=(+4.0\times 10^{-6}) +(20\times 10^{-6})[/tex]
[tex]=24.0\times 10^{-6} \ C[/tex]
hence,
After separation, the charge on each sphere will be:
⇒ [tex]q=\frac{Q}{2}[/tex]
[tex]=\frac{24.0\times 10^{-6}}{2}[/tex]
[tex]=12\times 10^{-6} \ C[/tex]
