Answer:
The velocity at t = 6 is of -166 units of velocity.
Step-by-step explanation:
Velocity function:
The velocity function is the integral of the acceleration function.
We have that:
The acceleration function is:
[tex]a(t) = 12 - 4t^2[/tex]
So the velocity function is:
[tex]v(t) = \int a(t) dt = \int (12 - 4t^2) dt = 12t - \frac{4t^3}{3} + K[/tex]
In which K is the constant of integration, which is v(0).
v(0)=50
This means that:
[tex]v(t) = 12t - \frac{4t^3}{3} + 50[/tex]
What is the velocity at t=6?
[tex]v(6) = 12*6 - \frac{4*6^3}{3} + 50 = -166[/tex]
The velocity at t = 6 is of -166 units of velocity.
