There are two numbers, one is 7 more than twice the other. The sum of the numbers is 43. Make the equation to find the smaller number. Find the two numbers. Answer: If the smaller number is x, the equation will be . The numbers in ascending order are:
BRAINLIEST IF CORRECT

Respuesta :

Answer:

Smaller number: 12

Greater number: 31

Step-by-step explanation:

Hi there!

Let x equal to the smaller number.

Let y be equal to the greater number.

1) Translate the information into equations

"One is 7 more than twice the other"

⇒ [tex]y=2x+7[/tex]

"The sum of the numbers is 43"

⇒ [tex]x+y=43[/tex]

2) Use substitution to solve for the smaller number

[tex]x+y=43[/tex]

Plug the equation [tex]y=2x+7[/tex] into the above equation

[tex]x+(2x+7)=43\\x+2x+7=43\\3x+7=43[/tex]

Subtract both sides by 7

[tex]3x+7-7=43-7\\3x=36[/tex]

Divide both sides by 3 to isolate x

[tex]\frac{3x}{3} = \frac{36}{3} \\x=12[/tex]

Therefore, the smaller number equates to 12.

3) Use substitution to solve for the greater number

[tex]x+y=43[/tex]

Plug in x as 12

[tex]12+y=43[/tex]

Subtract both sides by 12 to isolate y

[tex]12+y-12=43-12\\y=31[/tex]

Therefore, the greater number equates to 31.

I hope this helps!