Answer: The value of [tex]\Delta G_{rxn}[/tex] for given equation is 119.096 kJ.
Explanation:
Given: [tex]\Delta H = 163.2 kJ[/tex] (1 kJ = 1000 J) = 163200 J
[tex]\Delta S = -148 J/K[/tex]
T = 298 K
Formula used to calculate [tex]\Delta G_{rxn}[/tex] is as follows.
[tex]\Delta G_{rxn} = \Delta H - T \Delta S[/tex]
Substitute the values into above formula as follows.
[tex]\Delta G_{rxn} = \Delta H - T \Delta S\\= 163200 J - (298 \times -148 J/K)\\= 163200 J - 44104 J\\= 119096 J \\= 119.096 kJ[/tex]
Thus, we can conclude that the value of [tex]\Delta G_{rxn}[/tex] for given equation is 119.096 kJ.
