Answer:
[tex]3.5\:\mathrm{m/s^2}[/tex]
Explanation:
Newton's 2nd law is given as [tex]\Sigma F = ma[/tex].
To find the acceleration in the horizontal direction, you need the horizontal component of the force being applied.
Using trigonometry to find the horizontal component of the force:
[tex]\cos 45^{\circ}=\frac{x}{5},\\\frac{\sqrt{2}}{{2}}=\frac{x}{5},\\x=\frac{5\sqrt{2}}{2}[/tex]
Use this horizontal component of the force to solve for for the acceleration of the object:
[tex]\frac{5\sqrt{2}}{2}=1.0\cdot a,\\a=\frac{5\sqrt{2}}{2}\approx \boxed{3.5\:\mathrm{m/s^2}}[/tex]
