Answer:
[tex]\lambda=1.37\times 10^{-11}\ m[/tex]
Explanation:
Give that,
The potential difference of the electrons, [tex]V=8\times 10^{3}\ V[/tex]
We need to find the wavelength of the electrons.
Using the conservation of energy,
[tex]2meV=\dfrac{h^2}{\lambda^2}\\\\\lambda=\sqrt{\dfrac{h^2}{2meV}}[/tex]
Put all the values,
[tex]\lambda=\sqrt{\dfrac{(6.63\times 10^{-34})^2}{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 8\times 10^3}}\\\\\lambda=1.37\times 10^{-11}\ m[/tex]
So, the wavelength of the electrons is [tex]1.37\times 10^{-11}\ m[/tex].
