Given:
The diagram of a circle.
[tex]m\angle BPV=124^\circ ,m\angle VPE=30^\circ ,m\angle EPF=76^\circ, m\angle FPD=48^\circ[/tex].
To find:
The measure of arc BEF.
Solution:
The measure of central angle is equal to the measure of corresponding arc.
So, in the given figure,
[tex]n(arcBV)=124^\circ ,m(arcVE)=30^\circ ,m(arcEF)=76^\circ, m(arcFD)=48^\circ[/tex]
Now,
[tex]m(arcBEF)=m(arcBV)+m(arcVE)+m(arcEF)[/tex]
[tex]m(arcBEF)=124^\circ +30^\circ+76^\circ[/tex]
[tex]m(arcBEF)=230^\circ[/tex]
Therefore, the measure of arc BEF is 230 degrees.
