How much would you need to deposit into an account that pays 6.5% interest compounded semiannually to have $10,000 after 7 years?

Respuesta :

Answer:

6390.56

Step-by-step explanation:

[tex]AV=PV(1+\frac{i}{n})^{nt}\\10000=x(1+\frac{.065}{2})^{7*2}\\10000=1.564807232*x\\6390.53=x[/tex]

9514 1404 393

Answer:

  $6490.57

Step-by-step explanation:

The future value is given by the compound interest formula ...

  A = P(1 +r/n)^(nt)

Principal P earns annual rate r compounded n times per year for t years.

Filling in the given values, we have ...

  10000 = P(1 +0.065/2)^(2·7) = P(1.0325^14)

  P = 10000/1.0325^14 ≈ 6390.5635

You would need to deposit $6390.57 into the account to have $10,000 in 7 years.

_____

Additional comment

Using the rounded-down result of the computation will result in a value after 7 years of $9,999.99, not quite $10,000. Rounding the computed value up to $6390.57 ensures the account balance will actually be $10,000.00 after 7 years.

If the balance is rounded to the nearest penny each time interest is added, then the balance after 7 years will be exactly $10,000.00. If there is no intermediate rounding, the resulting balance will be $10,000.01.

Most of the time, the answer key doesn't pay attention to details like this. Your expected answer may be $6390.56, or $6391 if rounded to dollars.