Two cyclists start at the same point and travel in opposite directions. One cyclist travels 10 kmh faster than the other. If the two cyclists are 162 kilometers apart after 3 hours, what is the rate of each cyclist?

Respuesta :

let x=rate of slower cyclist
x+9=rate of faster cyclist
distance=travel time*rate
..
3x+3(x+9)=99
3x+3x+27=99
6x=72
x=12
x+9=21
rate of slower cyclist=12 km/h
rate of faster cyclist=21 km/hr