Will give brainliest!! Using the measurements of the shapes.. determine the area and perimeter of the irregular polygon.

Answer:
[tex]p=28.2\:\text{units},\\A=40.2\:\text{square units}}[/tex]
Step-by-step explanation:
The irregular shape's area consists of the sum of the areas of all the shapes that make it up.
Area of pink triangle: [tex]\frac{1}{2}\cdot 3 \cdot 3=4.5[/tex]
Area of purple square: [tex]3^2=9[/tex]
Area of green quadrilateral: [tex]3\cdot 2.9=8.7[/tex]
Area of blue triangle: [tex]\sqrt{10.25(10.25-8.5)(10.25-6)(10.25-6)}=17.99989[/tex]
Therefore, the area of the irregular polygon is [tex]4.5+9+8.7+17.99989\approx \boxed{40.2\:\text{square units}}[/tex].
The perimeter of the irregular polygon consists of certain shred sides from the four polygons that make up:
[tex]p=3+3+3+4.2+3+6+6=\boxed{28.2\:\text{units}}[/tex]