Answer:
[tex]8\:\text{m/s}[/tex]
Explanation:
From Newton's 2nd Law, we have [tex]\Sigma F=ma[/tex]. Using this, we can find the acceleration of the object:
[tex]9.20=2.30a,\\a=\frac{9.20}{2.30}=4\:\mathrm{m/s^2}[/tex].
Now that we've found the block's acceleration, we can use the following kinematics equation to find its final velocity after 2 seconds:
[tex]v_f=v_i+at,\\v_f=0+4(2),\\v_f=\boxed{8\:\text{m/s}}[/tex]
*Assumption: The block is initially at rest and has a initial velocity of zero. Otherwise, the question is unsolvable.
