Answer:
Step-by-step explanation:
Segments AB and BC intersect each other at 90° at B.
Let the equation of the segment AB → y = mx + b
Here, m = Slope of the line
b = y-intercept
Slope of the line AB passing through A(14, -1) and B(2, 1)
Slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
     = [tex]\frac{1+1}{2-14}[/tex]
     = [tex]-\frac{2}{12}[/tex]
     = [tex]-\frac{1}{6}[/tex]
Equation of the line will be,
[tex]y=-\frac{1}{6}(x)+b[/tex]
Since, AB passes through (2, 1)
[tex]1=-\frac{1}{6}(2)+b[/tex]
[tex]b=1+\frac{1}{3}[/tex]
[tex]b=\frac{4}{3}[/tex]
Therefore, y-intercept of AB = [tex]\frac{4}{3}[/tex]
Equation of AB → [tex]y=-\frac{1}{6}(x)+\frac{4}{3}[/tex]
Since, line BC is perpendicular to AB,
By the property of perpendicular lines,
[tex]m_1\times m_2=-1[/tex]
Here, [tex]m_1[/tex] and [tex]m_2[/tex] are the slopes of line AB and BC respectively.
By this property,
[tex]-\frac{1}{6}\times m_2=-1[/tex]
[tex]m_2=6[/tex]
Equation of a line passing through a point (h, k) and slope 'm' is,
(y - k) = m(x - h)
Therefore, equation of line BC passing through B(2, 1) and slope = 6,
y - 1 = 6(x - 2)
y = 6x - 11
Since, line BC passes through C(x, 13),
13 = 6x - 11
6x = 24
x = 4
Therefore, x-coordinate of point C will be, x = 4
