Answer:
[tex]\text{b. }\sin \theta =\frac{3}{5}[/tex]
Step-by-step explanation:
In a right triangle only, the tangent of an angle is equal to its opposite side divided by its adjacent side. If [tex]\tan \theta =\frac{3}{4}[/tex] as given in the problem, then the opposite side of angle theta is 3 and its adjacent side is 4. Thus, the hypotenuse of the triangle must be [tex]h=\sqrt{4^2+3^2}=\sqrt{25}=5[/tex].
The sine of an angle in a right triangle is equal to its opposite side divided by its hypotenuse. Therefore, [tex]\sin \theta =\frac{3}{5}[/tex] (o/h).
