Answer:
Area = 12
Step-by-step explanation:
Given
See attachment
Required
Area of [tex]\triangle PQR[/tex]
From the attached image, we have:
[tex]P = (6,10)[/tex]
[tex]Q = (10,8)[/tex]
[tex]R = (6,4)[/tex]
The area is then calculated as:
[tex]A = \frac{1}{2}|(x1y2 - x2y1) + (x2y3 - x3y2) + (x3y1 - x1y3)|[/tex]
So, we have:
[tex]A = \frac{1}{2}|(6*8 - 10*10) + (10*4 - 6*8) + (6*10 - 6*4)|[/tex]
Using a calculator:
[tex]A = \frac{1}{2}|-24|[/tex]
Remove absolute bracket
[tex]A = \frac{1}{2} * 24[/tex]
[tex]A = 12[/tex]
