Answer:
1. 0.82 gram of Ag+
2. 4.79 g of Ag₂O₃S
Explanation:
From the given information:
Total amount of Ag₂O₃S = 2.24 grams
Atomic mass of Ag+ =107.86 g/mole
molar mass of Ag₂O₃S = 295.8 g/mole
∴
The mass of the Silver (Ag) in grams is:
[tex]= Total\ amount \ of \ Ag^+ \times \dfrac{107.86 \ g/mol}{295.8 \ g/mol}[/tex]
[tex]=2.24 \times \dfrac{107.86 \ g/mol}{295.8 \ g/mol}[/tex]
= 0.82 gram of Ag+
2.
Here, the total amount of Ag₂O₃S = unknown
Atomic mass of Ag+ = 107.86 g/mole
molar mass of Ag₂O₃S = 295.8 g/mole
amount of Ag+ = 1.75 g
∴
The mass of Ag₂O₃S = [tex]Total \ amount \ of \ Ag^+ \times \dfrac{295.8 \ g/mol}{107.86\ g/mol}[/tex]
[tex]=1.75 \times \dfrac{295.8 \ g/mol}{107.86\ g/mol}[/tex]
= 4.79 g of Ag₂O₃S
