Respuesta :
Given :
- total charge = 9.0 mC = 0.009 C
Each electron has a charge of :
[tex]1.6 \times 10 {}^{ - 19} \: C[/tex]
For producing 1 Cuolomb charge we need :
- [tex] \mathrm{\dfrac{1}{1.6 \times 10 {}^{ - 19} } }[/tex]
- [tex] \dfrac{10 {}^{19} }{1.6} [/tex]
- [tex] \dfrac{10\times 10 {}^{19} }{16} [/tex]
- [tex] \dfrac{100 \times 10 {}^{18} }{16} [/tex]
- [tex] \mathrm{6.24 \times 10 {}^{18} \: \: electrons}[/tex]
Now, for producing 0.009 C of charge, the number of electrons required is :
- [tex]0.009 \times 6.24 \times {10}^{18} [/tex]
- [tex]0.05616 \times 10 {}^{18} [/tex]
- [tex] \mathrm{5.616 \times 10 {}^{16} \: \: electons}[/tex]
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So, Number of electrons passing through the cross section in 3.6 seconds is :
[tex] \mathrm{5.616 \times 10 {}^{16} \: \: electrons} [/tex]
Number of electrons passing through it in 1 Second is :
- [tex] \dfrac{5.616 \times {10}^{16} }{3.6} [/tex]
- [tex] \mathrm{1.56 \times 10 {}^{16} \: \: electrons}[/tex]
Now, in 10 seconds the number of electrons passing through it is :
- [tex]10 \times \mathrm{1.56 \times 10 {}^{16} \: \: }[/tex]
- [tex] \mathrm{1.56 \times 10 {}^{17} \: \: electrons}[/tex]
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[tex]\mathrm{ \#TeeNForeveR}[/tex]
