Answer: [tex]18.798\times 10^5\ J[/tex]
Explanation:
Given
Mass of snow is [tex]m=3\ kg[/tex]
First snow is converted to water at [tex]0^{\circ}C[/tex] and then it is taken to [tex]70^{\circ}C[/tex]
Heat required to convert the ice into water at [tex]0^{\circ}C[/tex]
[tex]Q_1=3\times 3.34\times 10^5\\Q_1=10.02\times 10^5\ J[/tex]
Heat required to raise temperature from [tex]0^{\circ}C[/tex] to [tex]70^{\circ}C[/tex]
[tex]Q_2=3\times 4180\times (70-0)\\Q_2=8.778\times 10^5\ J[/tex]
Total heat required
[tex]\Rightarrow Q=Q_1+Q_2\\\Rightarrow Q=10.02\times 10^5+8.778\times 10^5\\\Rightarrow Q=18.798\times 10^5\ J[/tex]
