Answer:
The current needed is 2387.32 A
Explanation:
Given;
strength of the magnetic field, B = 1.5 T
length of the solenoid, L = 18 m
diameter of the solenoid, D = 75 cm = 0.75 m
diameter of the superconducting wire, d = 2 mm = 0.002 m
The number of turns of the solenoid is calculated as;
[tex]N = \frac{length \ of \ solenoid}{diameter \ of \ wire } = \frac{1.8}{0.002} = 900 \ turns[/tex]
The magnetic field strength is given by;
[tex]B = \frac{\mu_0 NI}{L} \\\\[/tex]
Where;
I is the current needed
Ī¼ā is permeability of free space = 4Ļ x 10ā»ā· T.m/A
[tex]I = \frac{BL}{\mu_0 N} =\frac{1.5 \times 1.8}{4\pi \times 10^{-7} \ \times 900} \\\\I = 2387.32 \ A[/tex]
Therefore, the current needed is 2387.32 A
