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Parallelogram CDEF is formed inside of rectangle AEBC to create triangle ADC and triangle EBF as shown in the model below.



How much greater is the area of parallelogram CDEF than the area of triangle EBF in square centimeters?

Parallelogram CDEF is formed inside of rectangle AEBC to create triangle ADC and triangle EBF as shown in the model below How much greater is the area of parall class=

Respuesta :

The areas of the parallelogram CDEF and triangle EBF can be calculated

from which the difference between the areas can be found.

Response:

  • The amount by which the area of parallelogram CDEF is greater than the area of triangle BF is C. 493.5 cm².

Which methods can be used to evaluate the areas of the regular shapes?

Area of the  parallelogram CDEF = CF × EB

Which gives;

Area of the  parallelogram CDEF, A = 29 cm × 21 cm = 609 cm²

Area of triangle EBF = [tex]\mathbf{\frac{1}{2}}[/tex] × BF × EB

Which gives;

Area of triangle EBF, [tex]A_{EBF}[/tex] = [tex]\frac{1}{2}[/tex] × 11 cm × 21 cm = 115.5 cm²

The difference in area, ΔA = A - [tex]\mathbf{A_{EBF}}[/tex]

Which gives;

ΔA = 609 cm² - 115.5 cm² = 493.5 cm²

  • The area of parallelogram CDEF is 493.5 cm² greater than the area of triangle BF

  • The correct option is C. 493.5 cm²

Learn more about the area of regular shapes here:

https://brainly.com/question/10572314

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