Answer:
The correct option is C: the normal force of gravity on each foot is equal to 1/2 the force of gravity on the person.
Explanation:
Since the feet are equidistant from each other, the total torque is zero:
[tex] \Sigma \tau = 0 [/tex]
And the total forces acting on the feet are also equal to zero:
[tex] \Sigma F = 0 [/tex]
Hence, the normal force on the feet are:
[tex] W = N_{1} + N_{2} [/tex]
Where:
W: is the weight force
N₁: is the normal force of foot 1
N₂: is the normal force of foot 2
Since the normal force of each foot is the same, we have that N₁ = N₂ so:
[tex] W = 2N [/tex]
[tex] N = \frac{W}{2} [/tex] (1)
From the result of equation (1), we have that the normal force on each foot is equal to 1/2 the force of gravity on the person.
Therefore, the correct option is C: the normal force on each foot is equal to 1/2 the force of gravity on the person.
I hope it helps you!
