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In a set of three lines, a pair of parallel lines is intersected by a transversal. The intersection forms eight special angles.

Two of the special angles, A and B, are corresponding angles.

For the set of parallel lines intersected by a transversal, A = 4x and B = 2(x+14).


1. Use an equation to represent the corresponding angle relationship between A and B.


2. Use the equation to find the measures of A and B.

PLEASE HELP!!! Will mark brainliest and give thanks:)

Respuesta :

Answer:

a.) 4x = 2(x + 14)

b.) Measure of A = 56°

    Measure of B = 56°

Step-by-step explanation:

We know that,

When two lines are crossed by another line transversal line , the angles in matching corners are called corresponding angles.

Also,

When two lines are parallel then the Corresponding Angles are equal.

Given that,

A = 4x and B = 2(x+14).

i.e.

∠A = 4x and ∠B = 2(x+14)

a.)

Now,

As A and B are parallel

So,

∠A = ∠B

⇒4x = 2(x + 14)                  

(This is the equation that represent the corresponding angle relationship between A and B.)

b.)

Now,

⇒4x = 2x + 2(14)

⇒4x = 2x + 28

⇒4x - 2x = 28

⇒2x = 28

⇒x = 14

So,

we get

∠A = 4(14)

      = 56

⇒∠A = 56°

and

∠B = 2(14 + 14)

     = 2(28)

     = 56°

⇒∠B = 56°

∴ we get

Measure of A = 56°

Measure of B = 56°

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