Respuesta :
Answer:
The Correct answer is D
Explanation:
The heat absorbed in Trial 2 is about 1,674 J greater than the heat absorbed in Trial 1.
The statement that is true about Jane's experiment is:
The heat absorbed in Trial 2 is about 1,674 J greater than the heat absorbed in Trial 1.
To solve this question, we'll begin by calculating the heat absorbed in each trial.
Trial 1:
Mass of water (M) = 80 g
Initial temperature of water (T₁) = 15 °C
Final temperature of water (T₂) = 65 °C
Change in temperature of water (ΔT) = T₂ – T₁
= 65 – 15
= 50 °C
Specific heat capacity of water = 4.184 J/gºC
Heat absorbed (Q₁) =?
Q₁ = MCΔT
Q₁ = 80 × 4.184 × 50
Q₁ = 16736 J
Trial 2:
Mass of water (M) = 80 g
Initial temperature of water (T₁) = 10 °C
Final temperature of water (T₂) = 65 °C
Change in temperature of water (ΔT) = T₂ – T₁
= 65 – 10
= 55 °C
Specific heat capacity of water = 4.184 J/gºC
Heat absorbed (Q₂) =?
Q₂ = MCΔT
Q₂ = 80 × 4.184 × 55
Q₂ = 18410 J
Finally, we shall determine the difference in the heat absorbed. This can be obtained as follow:
Heat absorbed in trial 1 (Q₁) = 16736 J
Heat absorbed in trial 2 (Q₂) = 18410 J
Difference =?
Difference = Q₂ – Q₁
Difference = 18410 – 16736
Difference = 1674 J
From the calculations made above, we see that the heat absorbed in trial 2 is 1674 J greater than the heat absorbed in Trial 1.
Therefore, the correct statement is: The heat absorbed in Trial 2 is about 1,674 J greater than the heat absorbed in Trial 1.
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