Respuesta :
Answer:
Solution given:
Let AB be distance between tower ,angle of elevation be<A and height of tower be BC.
we have
<A=45°
AB=200ft
BC=?
Relationship between base and perpendicular is given by tan angle.
tan A=[tex] \frac{perpendicular }{base} [/tex]
tan 45°=[tex] \frac{BC }{AB} [/tex]
1=[tex] \frac{BC }{200ft} [/tex]
doing crisscrossed multiplication
BC=200ft
the height of the tower is 200ft.

So
- tanØ=Perpendicular/Base
Height is perpendicular
- tan45=perpendicular/200
- perpendicular=200tan45
- perpendicular=200ft
