Answer:
The right solution is "y(0) = 30 m" and "y'(0) = -6 m/s²".
Step-by-step explanation:
Given,
Velocity,
u = -6 m/s
Height,
h = 30 m
Now,
By using shifting of origin, we get
⇒ [tex](y-30)=-6t+\frac{1}{2}(-9.8)t^2[/tex]
[tex]y-30=-6t-4.9t^2[/tex]
[tex]y=30-6t-4.9t^2[/tex]
hence,
The value of y(0) is:
y(0) = [tex]30-0-0[/tex]
= [tex]30 \ m[/tex]
The value of y'(0) is:
y'(t) = [tex]-6-9.8t[/tex]
y'(0) = [tex]-6 \ m/s^2[/tex]
