A local charity holds a carnival to raise money. In one activity, participants make a $3 donation for a chance to spin a
wheel that has 10 spaces marked with the values 0, 1, 2, 5, and 10. The participant wins the dollar amount marked on
the space on which the wheel stops. Let X represent the value of a spin. The distribution of X is given in the table.
a.1 b.1.5 c.2 d.2.1

A local charity holds a carnival to raise money In one activity participants make a 3 donation for a chance to spin a wheel that has 10 spaces marked with the v class=

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Answer:

The  median of the distribution is (first option);

1

Step-by-step explanation:

The values on the given table are presented as follows;

[tex]\begin{array}{cccccc}Value \ of \ Spin&0&1&2&5&10\\Probability&0.4&0.2&0.2&0.1&0.1\end{array}[/tex]

To find the median, we calculate the cumulative probabilities to find the value of the spin art which the cumulative probability is 0.5 as follows;

Cumulative probability, starting from the left, is therefore;

Probability for spin of 0, 0.4 + Probability for spin of 1, 0.2 = 0.6

Therefore, given that the probability of 0.5 occurs within the Value of Spin 1, the median of the probability distribution is 1

The median value of the distribution of X is 1

How to determine the median?

The cumulative probability of the distribution is:

[tex]\sum E(x) = 1[/tex]

The median position is calculated as:

[tex]Median = \frac{\sum E(x)}{2}[/tex]

This gives

[tex]Median = \frac{1}{2}[/tex]

Median = 0.5 th

This mean that the median is at the 0.5th position

The value of the spin at the 0.5th position is 1

Hence, the median value of the distribution of X is 1

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