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In ΔMNO, the measure of ∠O=90°, OM = 69 feet, and NO = 16 feet. Find the measure of ∠N to the nearest tenth of a degree.

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sqdancefan

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Answer:

  76.9°

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

  tan(N) = OM/ON

  N = arctan(OM/ON) = arctan(69/16)

  N ≈ 76.9°

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