A boat traveled 448 miles downstream and back. The trip downstream took 14 hours. The trip back took 16 hours. B) boat: 30 mph, current: 2 mph.
How to find the speed of an object?
If the object is going linearly, and at a constant speed, then the speed of that object is given by the distance it traveled to the time it took to travel that distance.
If the object traveled D distance in T units time, then that object's speed is
[tex]Speed = S = \dfrac{\: Distance \: traveled}{\: Time \: taken} = \dfrac{D}{T} \: \rm unit \: length/unit \: time[/tex]
A boat traveled 448 miles downstream and back.
The trip downstream took 14 hours. The trip back took 16 hours.
[tex]S = \dfrac{D}{T} \: \rm unit \: length/unit \: time[/tex]
Speed of downstream
448/ 14= 32
Speed of back stream
448 / 16= 28
B = Speed of boat in the water
Y = Speed of current
The system of equation
B + y = 32
B - y = 28
32 + 28 =60
60 / 2 = 30
So,
32 - 30 =2
B = 30
Y = 2
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