Answer:
pH = 13.1
Explanation:
Hello there!
In this case, according to the given information, we can set up the following equation:
[tex]HCl+KOH\rightarrow KCl+H_2O[/tex]
Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:
[tex]n_{HCl}=0.012L*0.16mol/L=0.00192mol\\\\n_{KOH}=0.032L*0.24mol/L=0.00768mol[/tex]
Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:
[tex]n_{KOH}=0.00768mol-0.00192mol=0.00576mol[/tex]
And the resulting concentration of KOH and OH ions as this is a strong base:
[tex][KOH]=[OH^-]=\frac{0.00576mol}{0.012L+0.032L}=0.131M[/tex]
And the resulting pH is:
[tex]pH=14+log(0.131)\\\\pH=13.1[/tex]
Regards!
