Respuesta :
The solution to the equation are (0, 0) and (11/2, -22) after solving the equation by substitute method.
What is a quadratic equation ?
Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
[tex]\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]
We have system of equation:
y = –4x ..(1)
y = 2x² – 15x ..(2)
Plug the value of y in the equation (2)
-4x = 2x² – 15x
2x² – 15x +4x = 0
2x² - 11x = 0
x(2x - 11) = 0
x = 0 or x = 11/2
Plug this values in the equation (1)
y = 0, or y = -22
Thus, the solution to the equation are (0, 0) and (11/2, -22) after solving the equation by substitute method.
Learn more about quadratic equations here:
brainly.com/question/2263981
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